🌱Energy & Environment

How to Calculate Heat Pump Savings and Payback

Whether a heat pump costs less to run than your current heating, and how long the extra installation cost takes to recover, depends on your own numbers: how much heat the home needs, the efficiency of your current system, the heat pump's seasonal efficiency in your home, and your fuel and electricity prices. Not every household will save money. This guide shows how to compare the cost of useful heat, runs several illustrative scenarios — including one where the heat pump costs more — and explains why payback is so sensitive to assumptions. What COP and SCOP mean is covered in the COP and SCOP guide.

9 min read
July 7, 2026
Updated: Oct 5, 2026
Air-source heat pump installed beside a Scandinavian home in winter
Seasonal performance depends on the equipment, the climate and the heating system it is connected to.

Compare the Cost of Useful Heat, Not Input Energy

Comparing fuel and electricity prices per kWh on their own is misleading. A boiler turns only part of its fuel into heat in the home, while a heat pump delivers more heat than the electricity it uses. The fair comparison is the cost of each kWh of heat delivered:

Cost per kWh of heat = Price per kWh of input energy ÷ Seasonal efficiency

For a boiler the efficiency is below 1 (for example 0.90); for a heat pump it is the seasonal performance, SCOP or a measured seasonal figure.

Cost per kWh of Heat — Illustrative

Gas €0.11/kWh ÷ 0.90 boiler efficiency = €0.122 per kWh of heat Electricity €0.28/kWh ÷ SCOP 3.5 = €0.080 per kWh of heat Per kWh of input, electricity looks 2.5 times as expensive; per kWh of heat, the heat pump is cheaper in this example. With other prices or a lower seasonal efficiency, it may not be.

Step 1 — Your Current Heating System and Fuel

Identify what you would replace and its seasonal efficiency in your home:

  • Gas, oil or LPG boiler — use a seasonal efficiency, not the peak figure on the box; older boilers and boilers running at high return temperatures are usually less efficient than their rating. The product label or datasheet is a starting point.
  • Direct electric (resistance) heating — efficiency is about 1: each kWh of electricity gives about 1 kWh of heat.
  • District heating or wood — compare the delivered-heat price your bill or supplier states.

If the existing boiler also heats hot water, the comparison should include hot water for both systems.

Step 2 — Your Delivered Heat Demand

Heat demand is the useful heat the home needs over a year, in kWh. From bills:

Heat demand ≈ Fuel used (kWh) × Current system efficiency

Illustrative: 15,000 kWh of gas at 90% ≈ 13,500 kWh of heat. If your bill shows gas in m³, MJ or therms, convert it first with the gas to kWh converter, therms to kWh or MJ to kWh. If gas also covers cooking, subtract an estimate for it.

Without usable bills — or if you will insulate first — an installer's heat-loss calculation gives a design estimate. Heat demand varies with the weather year, so an average of several years is more reliable than one.

Step 3 — The Heat Pump’s Seasonal Efficiency in Your Home

Use a seasonal figure for the specific model, for the climate and flow temperature closest to your installation — from the datasheet, label or installer design. Climate, the home's heat loss, emitter size and flow temperature, and any backup resistance heat all move the real seasonal figure. The COP and SCOP guide explains these ratings and how to choose the right one; for the cost calculation, test a range rather than a single value.

Step 4 — Fuel and Electricity Prices

  • Use unit rates per kWh from your own tariffs, converted to the same unit.
  • Standing charges — if switching lets you close your gas connection, the gas standing charge you no longer pay is an additional saving; if you keep gas for cooking, it is not.
  • Time-of-use electricity — a heat pump runs mostly when heat is needed, so use a weighted rate for those hours rather than the cheapest night rate, unless the system is designed to shift load (for example with a hot-water cylinder or buffer).
  • Oil and LPG — prices per litre need converting to per kWh using the fuel's energy content; the Heat Pump Savings Calculator does this for you.

The Annual Running-Cost Formula

With heat demand, both efficiencies and both prices, the running costs follow directly:

Annual Cost Comparison — Illustrative Example

Current cost = Heat demand ÷ Current efficiency × Fuel price Heat pump cost = Heat demand ÷ Seasonal efficiency × Electricity price Annual saving = Current cost − Heat pump cost Illustrative inputs (replace with your own): Heat demand 15,000 kWh/year, boiler efficiency 90%, gas €0.11/kWh SCOP 3.5, electricity €0.28/kWh Boiler: 15,000 ÷ 0.90 × €0.11 = €1,833 Heat pump: 15,000 ÷ 3.5 × €0.28 = €1,200 Saving: €633/year

The Break-Even Price Ratio

Setting the two running costs equal gives a quick test. The heat pump is cheaper to run when:

Electricity price ÷ Fuel price < Seasonal efficiency ÷ Current efficiency

Both prices must be per kWh. In the example: 0.28 ÷ 0.11 = 2.55, and 3.5 ÷ 0.90 = 3.89, so the heat pump is cheaper. With SCOP 2.5: 2.5 ÷ 0.90 = 2.78 — still above 2.55, but only just, so the saving is small.

Seasonal efficiencyBreak-even price ratio at 90% boiler efficiency
2.52.78
3.03.33
3.53.89
4.04.44
Boiler room with copper pipework and wall-mounted heat pump indoor unit
Existing radiators can often be reused if they deliver enough heat at the lower flow temperature the heat pump is designed for.

Backup Resistance Heat

If a backup resistance heater supplies part of the year's heat — in very cold weather, during defrost or for hot water — that part runs at an efficiency of about 1. The effective seasonal efficiency is then lower than the heat pump's own rating.

Backup Heat — Illustrative Example

Heat demand 15,000 kWh; heat pump supplies 90% at SCOP 3.5, backup heater 10% Heat pump: 13,500 ÷ 3.5 = 3,857 kWh Backup: 1,500 ÷ 1.0 = 1,500 kWh Total electricity: 5,357 kWh → effective seasonal efficiency 15,000 ÷ 5,357 = 2.80 Cost at €0.28/kWh: €1,500, against €1,833 for the boiler → saving €333/year instead of €633.

Worked Scenarios

Each row changes the illustrative base case (15,000 kWh heat, gas €0.11/kWh at 90%, SCOP 3.5, electricity €0.28/kWh) as described. None describes a real country, tariff or product.

A heat pump does not always cost less to run

Scenario G shows that with expensive electricity relative to gas, even a reasonable seasonal efficiency can give higher running costs. Run the calculation with your own prices before assuming a saving.
Scenario (illustrative)Current costHeat pump costAnnual saving
A. Base case€1,833€1,200€633
B. Seasonal efficiency 2.5 (high flow temperature)€1,833€1,680€153
C. 10% backup resistance heat€1,833€1,500€333
D. Low heat demand, 8,000 kWh€978€640€338
E. Oil boiler, 85%, oil €0.12/kWh€2,118€1,200€918
F. Direct electric heating replaced€4,200€1,200€3,000
G. Electricity €0.40, gas €0.10€1,667€1,714−€48 (costs more)

Installation Cost and Payback

If your current system needs replacing anyway, the relevant cost is the extra cost of the heat pump over a like-for-like replacement, after any grant. If it does not, the full installed cost counts. Include any extra work the heat pump needs — larger radiators, a hot-water cylinder, electrical upgrades.

Any difference in annual maintenance between the two systems belongs in the saving: Annual net saving = Running-cost saving − Extra maintenance cost (which may be negative if the heat pump costs less to maintain). Ask installers for their service requirements; this guide assumes none in the examples.

Payback Formula — Illustrative Example

Payback = (Heat pump installed cost − Replacement boiler cost − Grant) ÷ Annual net saving Illustrative: heat pump €14,000, boiler €4,500, grant €5,000 → extra cost €4,500 Annual saving €633.33 (unrounded €1,833.33 − €1,200) Payback = 4,500 ÷ 633.33 ≈ 7.1 years 15-year saving at constant prices = 15 × €633.33 = €9,500 → net €5,000

Why Payback Is So Assumption-Sensitive

Payback divides a fixed cost by a saving that is the difference between two larger numbers. Small changes in either running cost therefore cause large changes in the saving, and larger changes in payback. With the same €4,500 extra cost:

Test a range, not a point

Run the Heat Pump Savings Calculator with a low, central and high seasonal efficiency and with alternative price ratios. If the decision only works under the most favourable assumptions, treat it as uncertain.
ScenarioAnnual savingSimple payback
A. Base case€6337.1 years
C. 10% backup heat€33313.5 years
D. Low heat demand€33813.3 years
B. Seasonal efficiency 2.5€15329.3 years
G. Expensive electricity−€48Never at these prices

Grants and Subsidies

Grant schemes, tax credits and eligibility rules differ by country and region and change frequently, so this guide lists no amounts. Check the official programme page for your area, and enter only support you are actually eligible for.

Underfloor heating pipes being installed during renovation
Lower flow temperatures, such as with underfloor heating, generally help seasonal efficiency.

When the Numbers Are Weak

These situations commonly weaken the result — check them with your own inputs:

  • High flow temperatures — radiators that need very hot water lower seasonal efficiency. Larger emitters or better insulation can allow lower temperatures; see the DIY home energy audit guide.
  • Electricity expensive relative to fuel — if your price ratio is close to the break-even ratio, savings are small or negative.
  • Cold climate with unsuitable equipment — check the model's capacity and performance at your design outdoor temperature, and how much backup heat the design assumes.
  • Low heat demand — the saving scales with heat demand while installation cost does not.
  • Short ownership period — if you expect to move before payback, the financial case weakens.

Reduce Heat Demand First Where It Is Cheap

Every kWh of heat demand removed saves money with either system and can allow a smaller heat pump and lower flow temperature. Use the Home Energy Audit Calculator to see where your energy goes.

Run Your Own Comparison

The Heat Pump Savings Calculator applies the formulas above: enter your heat demand or fuel use, current fuel, efficiency and price, electricity price, seasonal efficiency and net installation cost. It returns both running costs, the annual saving, the break-even seasonal efficiency and electricity price, and simple payback. Its defaults are placeholders. The methodology page documents the formulas and sources, and the Heat Pumps hub collects the related tools and guides.

❓Frequently Asked Questions

Divide your electricity unit price by your gas unit price (both per kWh) and multiply by your boiler efficiency. The heat pump’s seasonal efficiency must be higher than that. Example: €0.28 ÷ €0.11 = 2.55; × 0.90 = 2.29. The saving is small until the seasonal efficiency is well above that threshold.